Question

A stone of mass 1kg is tied with a string and it is whirled in a vertical circle of radius 1m

Answer 1

Answer:

Vtop = 3.132 m/s

Explanation:

As it is not asked anything in the question, I will calculate all the parameters that can be derived.

Given Data, mass m=1 kg, radius r = 1m.

• The minimum speed for the mass at the top of circle = $\sqrt{gr}$

         $v= \sqrt{9.81 * 1} = 3.132 m/s$

• Tension in the string at the top of circle $T_{top} = \frac{mv_{top}^2}{r}-mg$

         T = 9.81-9.81 = 0

• Tension in the string at the bottom of the circle

         $T_{bottom} = T_{top}+ 6mg$ = 6*9.81 = 58.86 N

• The speed at the bottom

         $T_{bottom} = \frac{mv_{bottom}^2}{r}+mg$

          $58.86 = v_{bottom}^2 +9.81$

          solving the above equation,

          $v_{bottom} = 7.05\; m/s$