Question

A stone of mass 2.0kg, initially at rest, suddenly breaks into two pieces of masses 1.2kg and 0.8 kg respectively. If the lighter fragment travels with a velocity of 3.0 ms-1 in the direction of East, then find the velocity and direction of motion​

Answer 1

$2</p><p></p><p>Total mass of the body  M=1 kg</p><p></p><p>So, mass of first fragment  m1=51×1=0.2 kg</p><p></p><p>Mass of second fragment  m2=51×1=0.2 kg</p><p></p><p>Mass of third fragment  m3=53×1=0.6 kg</p><p></p><p>Velocity of masses m1 and m2,  v=30 m/s</p><p></p><p>Momentum of first fragment  p1=m1v=0.2×30=6 kg m/s</p><p></p><p>Similarly,  p2=m2v=0.2×30=6 kg m/s</p><p></p><p>Third fragment will fly in a direction opposite to the direction of resultant of p1 and p2 so that total momentum of the system after explosion remains zero.</p><p></p><p>Momentum of the third fragment  p3=p12+p22</p><p></p><p>∴  p3=62+62=62 kg m/s</p><p></p><p>Thus speed of third fragment  v3=m3p3=0.662=102 m/s</p><p></p><p>⟹ x=2</p><p></p><p>$

Answer 2

Answer:

your answer is in the attachment