Question

A stone of mass 2.0kg is attached to one end of a string of length 1.5m .If the stone is swung round in a horizontal circle at 1 revolution per second, calculate the tension in the string . [π=3.14].

Answer 1

Explanation:

If a string with a body is rotated in horizontal plane, there is no affect of weight of the body on tension (since it acts perpendicularly downward).

The only force acting on the body is the centripetal force.

So here tension acting on string, T=Fc=mw^(2) r = (mv^2) / r

= 2 x (2π)^2 x 1.5

=118.3152 N

Here angular velocity,w= 2π rads-1

since 1 revolution=2π rad