Question

A Stone of mass 2.0kg is attached to one end of a string of length 1.5m. If the stone is swung round in a horizontal circle at 1 revolution per second, calculate the tension in the string.

Answer 1

Answer:

Explanation:

Answer

Mass, m=0.2 kg

Radius, r=1 m

Angular speed, ω=90 rpm

⟹ω=  

60

90

​

 

⟹ω=1.5 rps

⟹ω=3π rad/s

(a) Angular velocity, ω=3π rad/s

(b) Centripetal acceleration. a=rw  

2

 

⟹a=1×3π×3π

⟹a=9π  

2

 m/s  

2

 

(c) Centripetal Force, F=ma

⟹F=0.2×9π  

2

 

⟹F=1.8π  

2

 N

(d) Tension in string, = Centripetal Force

⟹T=F=1.8π  

2

 N

Answer 2

Hope its helpful for you.