Question

A stone of mass 2.0kg is attached to one end of a string of length 1.5 m . If the stone is swung round in a horizontal circle at 1 revolution per second,calculate the tension in the string .3.14

Answer 1

$\sf\small\green{Given:-}$

$\bullet \rm \: mass = 2.0kg$

$\bullet \rm \: length = 1.5m$

$\bullet \rm \: revolution = 1$

$\sf\small\green{Find:-}$

$\bullet \rm \: calculate \: the \: tension \: in \: the \: string.$

$\sf\small\green{Solution:-}$

$\rm\rightarrow \: f = ma$

= 2 × 10N

=20 N

$\rm\rightarrow \: w = \sqrt{ \frac{f}{mr} } = \sqrt{ \frac{20}{1 \times 2} }$

$\rm\rightarrow \: w = \sqrt{10} = 3.14$

Now,

$\rm\rightarrow \: w = 2\pi \: n$

$\rm\rightarrow \: n = \frac{w}{2\pi}$

$\rm\rightarrow \: \frac{3.16}{2 \times 3.14}$

$\rm\dashrightarrow \fbox \red{0.50} \dashleftarrow$