Question

A stone of mass 2 kg hits on a floor with a speed 30 m/s. Calculate the momentum

of the stone when it just hit the floor.​

Answer 1

Given

• Mass = 2 kg
• Velocity = 30 m/s

To Find

• The momentum of the stone

Solution

☯ p = mv

• Where p denotes the moment of the body, m denotes it's mass & v denotes it's velocity

━━━━━━━━━━━━━━━━━━━━━━━━━

✭ According to the Question :

➞ p = mv

• p = Momentum = ?
• m = Mass = 2 kg
• v = Velocity = 30 m/s

➞ p = 30 × 2

➞ p = 60 kg m/s

∴ The momentum of the stone is 60 kg m/s

Answer 2

Answer:

Given :-

• A stone of mass 2 kg hits on a floor with a speed of 30 m/s.

To Find :-

• What is the momentum of the stone when it just hit the floor.

Formula Used :-

$\longmapsto \sf\boxed{\bold{\pink{p =\: mv}}}$

where,

• p = Momentum
• m = Mass
• v = Velocity

Solution :-

Given :

• Mass (m) = 2 kg
• Velocity (v) = 30 m/s

According to the question by using the formula we get,

$\implies \sf p =\: 2\: kg \times 30\: m/s$

$\implies \sf\bold{\red{p =\: 60\: kg\: m/s}}$

$\therefore$ The momentum of the stone when it just hit the floor is 60 kg m/s .

$\rule{150}{2}$

EXTRA INFORMATION :

$\diamondsuit$ The S.I unit of mass is kilogram (kg).

$\diamondsuit$ The S.I unit of time is second.

$\diamondsuit$ The S.I unit of temperature is kelvin.

$\diamondsuit$ The S.I unit of electric current is ampere.