Question

A stone of mass 2 kg is dropped from rest. What will be the kinetic energy at the end of 6 seconds?

Answer 1

Explanation:

given :

mass= 2 kg

u = 0 m/s

g = 9.8 m/s²

time = 6s

for finding kinetic energy we also know final velocity =

by using equation of motion

$v = u + at$

v= 0 +( 9.8 × 6 )

v = 58. 8m/s

now,

ke = ½mv²

ke= ½×2×(58

6)²

then kinetic energy⚡ = 58.6