Physics, asked by aaamir749749, 1 month ago

A stone of mass 2 kg is dropped from the top of a tower of height 40m. What will be its K.E. 10 m below the top?

Answers

Answered by Anonymous

1

Answer:

KE= mg (Htop- Hcurrent) = 1.0*9.8*10 = 98 (kgm^2/s^2)

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