Question

a stone of mass 2 kg is falling form rest from a hill. what will be its kinetic energy after 5s​

Answer 1

Kinetic energy = (mass×(velocity)^2)/2

1) mass of the stone is = 2

2)velocity is (10*5) = 50

:- kinetic energy = (2*(50)^2)/2

the answer is 2500

Answer 2

Answer:

u=0 (because initially the object was in rest)

Lets take a or g=9.8m/s^2

Now, v=u+at

= v= 0+ 9.8*5

=v =49m/s

Now, kinetic energy=1/2mv^2

1/2*2*49*49

=2401 joule

Therefore, kinetic energy =2401 joule

Explanation: