A stone of mass 2 kg is falling from rest from the top of a steep hill what will be its kinetic energy after 5 seconds
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for a falling object, vf=v0+gt....v0=0
vf(at t=5 sec)=(9.81*5)=49.05 m/sec
KE=1/2mv^2=(1/2)*(2kg)*(49.05)^2=2405.9025 J.
for a falling object, vf=v0+gt....v0=0
vf(at t=5 sec)=(9.81*5)=49.05 m/sec
KE=1/2mv^2=(1/2)*(2kg)*(49.05)^2=2405.9025 J.
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