a stone of mass 2 kg is falling from rest from the top of a step hill . what will be its kinetic energy after 5 sec ( g = 10 ms-2 )
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Mass of stone = 2 kg
Time =5sec
Let g=a=10 ms-2
Acceleration (a)= velocity /time
Velocity= a/time
= 10/5=2 ms-2
Kinetic energy = 1/2mv2
= 1/2 * 2* (2)2
= 4
Time =5sec
Let g=a=10 ms-2
Acceleration (a)= velocity /time
Velocity= a/time
= 10/5=2 ms-2
Kinetic energy = 1/2mv2
= 1/2 * 2* (2)2
= 4
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