Question

A stone of mass 2 kg is projected upwards with kinetic energy of 98 j the height at which the kinetic energy of the body becomes half of its original value is given by

Answer 1

Height where its k.e would become 49 j is H , then P.E at height H = 98-49= 49 J = mgH , so H = 49 / (2*9.8) = 10/4 = 2.5 m