Question

a stone of mass 2 kg tied to one end of a string is whirled around a horizontal circle of radius 1.2 metre makes 30 Revolution per minute calculate angular velocity linear velocity and centripetal acceleration of the stone​

Answer 1

Answer:

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Explanation:

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Answer 2

Linear velocity, v = 3.76 m/s

Centripetal acceleration, $a=11.78\ m/s^2$

Explanation:

Given that,

Mass if the stone, m = 2 kg

Radius of the circle, r = 1.2 m

Angular speed of the stone, $\omega=30\ rev/min=3.14\ rad/s$

To find,

The angular velocity linear velocity and centripetal acceleration of the stone​.

Solution,

The relation between angular velocity and liner velocity is given by :

$v=r\omega\\\\v=1.2\times 3.14\\\\v=3.76\ m/s$

The centripetal acceleration of the stone is given by :

$a=\dfrac{v^2}{r}\\\\a=\dfrac{(3.76)^2}{1.2}\\\\a=11.78\ m/s^2$

Hence, this is the required solution.

Learn more,

Kinematics

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