Question

A stone of mass 2 kg tied to one end of a string of length
1 m and it is revolving in a vertical circular path. Find the
minimum velocity of the stone at the lowest point and
tension in the string. (g = 10 m/s) (2003.10)​

Answer 1

Answer:

u=√50m the velocity

T=120N tension of string

Explanation:

given: m=2kg

           r=1m

          g=10 m/s but org is 9.8 m/s

formula u=√5gr

    u=√5*10*1

    u=√50

T=m/r(u²+gr)

T=2/1{(√50)²+10}

T=2(50+10)

T=2*60

T=120N