A stone of mass 20 g falling from height of 2 km hits the ground
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The initial velocity = 0
The final velocity = v
S = 2 × 1000 = 2000m
g = 9.8
From the equation :
V² = u² + 2gs
V² = 0 + 2 × 9.8 × 2000
V² = 39200
V = √39200
V = 197.99 m/s
The kinetic energy = 1/2mv²
m = 20/1000 = 0.02Kg
= 1/2 × 197.99² × 0.02 = 392.00
= 392 Joules
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