Question

A stone of mass 20g falling from height of 2 km Hits the ground with a speed of 200m|s. The work done by the gravitational force is

Answer 1

Answer:

answer is

399.6Joule

Explanation:

explanation is in picture

Answer 2

Answer:

The work done by gravity is equal to 400J.

Explanation:

Given:

V = 200m/s

m = 0.02kg

$KE_{i}$ = 0J

Here,

The work done by gravity is denoted by $W_{g}$.

The mass of the stone is denoted by m.

The speed of the stone on the ground is denoted by V.

The initial kinetic energy is denoted by $KE_{i}$.

The final kinetic energy is denoted by $KE_{f}$.

Now,

By the equation,

$W_{g} =KE_{f}-KE_{i}$

$W_{g} =\frac{1}{2} mV^{2} - 0\\W_{g} =\frac{1}{2} \times 0.02\times 200^{2} \\W_{g} =400J$

So, the work done by gravity is equal to 400J.