Question

A stone of mass 22 grams is immersed completely in
a measuring
Cylinder containing water. Due to
stone ,
the water level in
cylinder rises by
17 me. What is the
density of the stone ?​

Answer 1

Answer:

this question is wrong

Explanation:

to measure the density of solid, we need final water level in cylinder & initial water level in cylinder

Answer 2

Answer:

Solution:

Mass of the stone = 22g

As the rise in the water level gives a measure of the volume of the stone, therefore the volume

of the stone = 17 ml = 17 cm cube

( :. 1 mL = 1 cm cube )

therefore

$p = \frac{m}{v} \\ = \frac{22}{17} = 1.29g {}^{3}$

the density of the stone is 1.29cm cube