Question

a stone of mass 22g is immersed completely in a measuring cylinder containing water. Dje to the stone, water level in the cylinder rises by 17ml. What is the density of stone?​

Answer 1

Explanation:

Mass of the stone = 22g

As the rise in the water level gives a measure of the volume of the stone, therefore the volume

of the stone = 17 ml = 17 cm cube

( :. 1 mL = 1 cm cube )

therefore

\begin{gathered}p = \frac{m}{v} \\ = \frac{22}{17} = 1.29g {}^{3}\end{gathered}p=vm=1722=1.29g3

the density of the stone is 1.29cm cube

Answer 2

Answer: 1.29 cm -cube

Explanation:

mass of a stone =22g

as the rise in the water level gives a measure of the volume of the stone, therefore the volume of the stone= 17ml= 17cm cube (1ml= 1cm cube)

therefore, p= m/v

= 22/17 = 1.29 cm -cube