Question

A stone of mass 22gram is immersed completely in a measuring cylinder containing water. Due to the mass of the stone the water level in the cylinder rises by 17 ml. What is the density of the stone?

Answer 1

Explanation: i don't know

Answer 2

Given:

A stone of mass 22 grams is immersed completely in water such that the water level rises by 17mL.

To Find:

The density of the stone.

Solution:

Mass of the stone, $m=22g$

We know that the volume of the water displaced is equal to the volume of the object immersed in the water.

So, the volume of the stone, $V=17mL=17cm^3$

The density of the stone, ρ $=m/V$

                                             $=22g/17cm^3$

                                             $=1.3g/cm^3$

Hence, the density of the stone is equal to $1.3g/cm^3$.

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