Question

A stone of mass 250 g is tied to a light rope of length 1 m and whirled horizontally at a constant speed of 2 m/s. The centripetal force acting on the stone is​

Answer 1

Answer:

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Explanation:

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Answer 2

Answer:

Frequency of revolution of stone,

f=40rev/min=

60

40

rev/s

Angular speed of the stone, ω=2πf

=2π×

60

40

=

3

4π

rads

−1

The centripetal force is provided by the tension (T) in the string

i.e. T=

r

mv

2

=mrω

2

=0.25×1.5×(

3

4π

)

2

N=6.48N≈6.6N

As the string can withstand a maximum tension of 200N.

∴T

max

=

r

mv

max

2

⇒v

max

=

m

rT

max

=

0.25

1.5×200

=34.64ms

−1

≈35ms

−1

T=6.6N,v

max

=35ms

−1

Explanation:

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