A stone of mass 2kg is dropped from the top of a hill. It takes 5 sec to reach the ground
Find the kinetic Energy. ?
(Take G= 10m/s)
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Given:
mass (m)= 2kg
time(t)= 5s
g= 10 m/s2
let the velocity = v
thus, speed = distance/ time => distance = speed * time
here, distance = height (h) => h= v*5= 5v
Kinetic Energy (K.E) =1/2 (m * v2)
=> 1/2 ( 2 * v2)
=> v2
Potential Energy(P.E) = mgh
=> 2 * 10* h = 2* 10 * 5v
=> 100v
According to law of conservation of energy the total mechanical energy of a body remains same throughout its activity.
Therefore,
P.E=K.E
v2 = 100v
v= 100 m/s
this
Kinetic energy = v2 = (100)^2= 10000J
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