Question

a stone of mass 2kg is dropped from the tower of height 40m . what will be the k.e 10m below the top​

Answer 1

Explanation:

Given :

• h=40 m
• m=2kg
• u=0m/s

Force due to air resistance f=20 N

Acceleration of the stone

• a = g−f/m=10 − 20/2 = 0 m/s²

Using v²-u²=2aS

∴ v² − 0 = 2(0)×40

⟹ v = 0m/s

Answer 2

Answer:

0m/s is correct answer

Explanation:

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