Question

A stone of mass 2kg is falling from rest from top of a steep hill what will be its kinetic energy after 5 seconds with g=10m/s?

Answer 1

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Heres u go


K.e.=mvsq/2
v =u+at
v=0+10×5
v=50
k.e.=2×50×50×1/2
=2500 j

Answer 2

We have

Mass , m = 5 kg

Initial velociy , u = 0 m/s

g = 10

Time , t = 5 sec

We know that

v = u + gt
= 0 + 10 × 5
= 50 m/s

K.E. after 5 sec = 1/2 × m × v^2
= 1/2 × 2 × 50 ×50
= 2500J