A stone of mass 2kg is rotated in a horizontal circle with velocity 10 m/s such that string remains horizontal. Tension in the string if its length is 2 m, will be?
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Answer:
20
Explanation:
Mass of stone(m) = 2Kg,
radius(r) = length of rope =2m,
Maximum tension (T
max
) = 400N
The maximum tension acts as the centripetal force for the circular motion of the stone.
Let v
max
be the maximum velocity.
Hence, F=T
max
=
r
mv
max
2
⇒v
max
2
=
m
T
max
×r
⇒v
max
=
m
T
max
×r
⇒v
max
=
2
400×2
⇒v
max
=20ms
−1
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