Question

A stone of mass 3kg is dropped from the top of a building. what will be it's velocity after two seconds​

Answer 1

Answer:

v = u + gt where u=0

v = 2× 9.8

v = 19.6 m/s2

Answer 2

Here,

u = 0

v = ?

a = 9.8 m/s^2

m = 3 kg

t = 2 sec

from second equation of motion,

v = u + at

v = 0 + 9.8 * 2

v = 19.6 m/s