Question

A stone of mass 3kg tied a the end of a string is rotated in a vertical circle of radius 5m at the cons tant speed of 5m/s.calculate the tensionin the string at the lowest point of the path

Answer 1

Answer:

Tension in the spring at lowest point = 44.43 N

Explanation:

Given data :

mass, m= 3 kg,

radius of string, r= 5m

speed, v = 5m/s

At lowest point of vertical circle, the gravitational force and centripetal force will be in the same direction i.e. downwards.

Therefore, Tension in the spring at the lowest point is equal to the sum of weight of the ball plus the centripetal force acting on it as :

$T=mg +\frac{mv^2}{r}$

∴ $T = 3*9.81 + \frac{3*5^2}{5} = 44.43\; N$