Physics, asked by Anonymous, 1 year ago

A stone of mass 400 g, when immersed completely

in water displaces 250 cm3 of water. The relative

density of the stone is​

Answers

Answered by Abhignaparupalli
8

mass of stone 400g

after displacing in water 250cm3

the relative density=

400/250

1.6grams

Answered by netta00
1

Answer:

Relative density  = 1.6

Explanation:

Given that

Mass off stone = 400 g

Volume displace = 250 cm³

If body is completely is immersed then the displace fluid volume will the volume of the body.

So volume of body ,V= 250 cm³

We know that

Mass = density x volume

400 g = ρ x 250

ρ = 1.6 g/cm³

We know that volume off water = 1000 kg/m³

                                                     = 1 g/cm³

Relative density = Density of body /Density of water

Relative density = 1.6 /1 = 1.6

Relative density  = 1.6

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