A stone of mass 4kg is whirled in a horizontal circle of radius 1m and makes 2rev/sec. the rotational kinetic energy of stone is?
Answers
Answered by
0
Answer:
1rev=44/7 m
2 rev= 88/7 m
2 rev/s means rotational velocity =88/7 m/s
therefore rotational kinetic energy=1/2 mv²=1/2×4×88/7×88/7 j=316 j
Similar questions