Physics, asked by kaaynaat86, 8 hours ago

A stone of mass 4kg is whirled in a horizontal circle of radius 1m and makes 2rev/sec. the rotational kinetic energy of stone is?​

Answers

Answered by RealSweetie
0

Answer:

1rev=44/7 m

2 rev= 88/7 m

2 rev/s means rotational velocity =88/7 m/s

therefore rotational kinetic energy=1/2 mv²=1/2×4×88/7×88/7 j=316 j

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