Question

A STONE OF MASS 500g IS RAISED FROM A HEIGHT OF 2m to 5m . FIND THE CHANGE IN POTENTIAL ENERGY.

Answer 1

Answer:

• The change in P.E (Δ U) is 15 J

Given:

1. Mass of stone (M) = 500 g = 0.5 Kg
2. Initial height (h₁) = 2 m
3. Final height (h₂) = 5 m

Explanation:

$\rule{300}{1.5}$

We Know,

$\bigstar\;\underline{\boxed{\sf \Delta U=U_{f}-U_{i}}}$

Here,

• ΔU Denotes Change in P.E
• U_{f} Denotes Final P.E
• U_{i} Denotes Initial P.E

Substituting the values,

$\longrightarrow\sf \Delta U=\bigg(Mg\;h_{2}\bigg)-\bigg(Mg\;h_{1}\bigg)\\\\\\\longrightarrow\sf \Delta U =Mg\times \bigg(h_{2}-h_{1}\bigg)\\\\\\\longrightarrow\sf \Delta U = 0.5\times 10\bigg(5-2\bigg)\\\\\\\longrightarrow\sf \Delta U =5\times 3\\\\\\\longrightarrow\sf \Delta U = 15\\\\\\\longrightarrow \large{\underline{\boxed{\red{\sf \Delta U = 15\;J}}}}$

∴ The change in P.E (Δ U) is 15 J.

$\rule{300}{1.5}$

Answer 2

$\huge\underline\mathbb\red{ANSWER:-}$

The change in P.E (Δ U) is 15 J