A stone of mass 50g is being rotated in a circle of radius of 50cm with a uniform speed of 2 m/s. What is the acceleration of the stone??
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The stone is being rotated in a circular path. So, Centripetal force must be acting on it. (As circular motion is not possible without centripetal force).
Moreover, as speed is uniform, the value of Tangential Acceleration (Acceleration parallel to direction of motion at each instant) is zero.
Value of Centripetal Acceleration is:
(v=speed , r=radius of path=0.5 m)
a = (v^2)/r
= (2^2)/0.5
= 8 m/s^2
Thus, acceleration of stone is 8 m/s^2
Moreover, as speed is uniform, the value of Tangential Acceleration (Acceleration parallel to direction of motion at each instant) is zero.
Value of Centripetal Acceleration is:
(v=speed , r=radius of path=0.5 m)
a = (v^2)/r
= (2^2)/0.5
= 8 m/s^2
Thus, acceleration of stone is 8 m/s^2
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