A stone of mass 64g is thrown vertically upwards from the ground with an initial speed of 20ms-1.The gravitational potential energy at the ground level is considered to be zero. Apply the principle of conservation of energy to calculate the potential energy at the maximum height attained by the stone
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Given,
Mass of the stone,m=64g;
Initial speed with which the stone is thrown,v=20m/s
Potential energy at top = K.E at ground
1/2MV square = 1/2×64/1000×20×20 = 128/10 =12.8j
HOPE! It helps you
Mass of the stone,m=64g;
Initial speed with which the stone is thrown,v=20m/s
Potential energy at top = K.E at ground
1/2MV square = 1/2×64/1000×20×20 = 128/10 =12.8j
HOPE! It helps you
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