Question

A stone of mass 750g is thrown vertically upward with a velocity of 10m/s find (1) potential energy at the greatest height(2) kinetic energy on reaching the ground. (g=10m/s²)

Answer 1

Answer:

mass*velocity*gravity=>750*10*10=75000

1/2*mass*velocity*velocity=>1/2*750*10*10=37500

Explanation:

potential energy=m*g*h

        AND

kinetic energy=1/2*mass*velocity*velocity

Answer 2

The potential energy at the greatest height and kinetic energy on reaching the ground are same i.e. 37.5 Joules.

Explanation:

Given that,

Mass of the stone, m = 750 g = 0.75 kg

Velocity of the stone, v = 10 m/s

To find,

(1) Potential energy at the greatest height

(2) Kinetic energy on reaching the ground.

Solution,

The potential energy is possessed by a body due to its height. Kinetic energy is possessed due to its motion.

At the greatest height, the kinetic energy is equal to its potential energy due to the conservation of energy such that,

$P=K=$

$K=P=\dfrac{1}{2}\times 0.75\times (10)^2$

K = P = 37.5 Joules

So, the potential energy at the greatest height and kinetic energy on reaching the ground are same i.e. 37.5 Joules.

Learn more,

conservation of energy

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