Question

A stone of mass 750g is thrown vertically upward with the velocity of 10/s2 calculate, the potential energy at the greatest height

Answer 1

Explanation:

$\small\textbf{Stone is thrown vertically upward at top of most point}</p><p>$

$\small\textbf{potential energy = kinetic energy}$

$\huge\bold{Given :-}$

• Mass is 750 g

• In term of kg : Mass is 0.75 kg .

• Velocity ( v ) = 10 m / sec

We have formula for kinetic energy :-

$\small\textsf{K.E. = 1 / 2 m v²}$

$\huge\bold{Solution :-}$

$\text{Putting values now :}$

$\text{K.E. = 1 / 2 × 0.75 × 10 × 10}$

$\text{K.E. = 1 / 2 × 75 J}$

$\text{K.E. = 37.5 J}$

$\text\red{Since K.E . = P.E.}$

$\text\red{Thus potential energy of stone is 37.5 J}$

$\huge\mathfrak\red{Thanks}$