A stone of mass 9 kg falls freely under gravity from a height of 75 cm. Calculate the velocity of the stone just before it touches the ground. Hence find the momentum that is imparted by the stone on the ground.
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K.E of ball before collision with sand=P.E at 50m height.
Work done by resistive force=P.E at 50m height.
F.d=mg×50
F= −1
5×10×50
negative sign due to displacement in sand is opposite to the resistance (F).
F=2500N
Velocity before collision w 1
ksand is v= 2g×50
N= 1000 =31.62m/s
Change in momentom=mv
F△t=5×31.62
t=0.0632sesc.
Explanation:
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