A stone of mass m at the end of a string of length l is whirled in a vertical circle at a constant speed. the tension in the string will be maximum when the stone is
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A stone of mass m and length l is whirled in a vertical circle at a constant speed v as shown in figure.
Then tension in the string will be maximum when stone is at the bottom .
Explanation :- at bottom free body daigram as shown in figure.
We know, according to Newton's law ,
Fnet = force act in the direction of centre - force act in the outward direction from centre .
mv²/l = T - W
Here T is the tension in string , W is weight of stone ,
T = mv²/l + mg [ W = mg ]
But at the highest position T = mv²/l - mg,
That's why highest tension in the string at bottom position .
Then tension in the string will be maximum when stone is at the bottom .
Explanation :- at bottom free body daigram as shown in figure.
We know, according to Newton's law ,
Fnet = force act in the direction of centre - force act in the outward direction from centre .
mv²/l = T - W
Here T is the tension in string , W is weight of stone ,
T = mv²/l + mg [ W = mg ]
But at the highest position T = mv²/l - mg,
That's why highest tension in the string at bottom position .
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Answer: At the bottom of the circle
Explanation: the tension is greatest when the stone is at the bottom of the circle
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