Question

A stone of mass m is projected from the ground level with a velocity of magnitude v at an angle with
the horizontal. The angular momentum of the stone at the instant it strikes the ground is
​

Answer 1

Answer:

At the highest point, velocity=vcos45

0

=

2

v

in horizontal direction

∴ Momentum=

2

mv

L= Angular momentum = Momentum × Perpendicular distance

L=

2

(h)

mv

Here h=

2g

v

2

sin

2

45

0

=

4g

v

2

∴L=

2

mv

4g

v

2

=

4

2

g

mv

3

Answer 2

Step-by-step explanation:

hope it will help you bro