Question

A stone of mass 'm' tied to a string of length 'l' is rotated in a circle with the other end of the string as the center. The speed of the stone is 'v'. If the string breaks, the stone will move
(a) towards the center
(b) away from the center
(c) along a tangent
(d) will stop

Answer 1

along tangent so answer is(c)

Answer 2

Answer ⇒ Along a tangent.  Option (c).

Explanation ⇒ A stone of mass 'm' tied to a string of length 'l' is rotated in a circle with the other end of the string as the center. The speed of the stone is 'v'. If the string breaks, the stone will move along a tangent, this is because in case of the circular motion, the direction of the velocity at every instant is along the tangent but the  object is balanced in circular path due to centripetal force and as soon as this force disappears the particles will leave the circle.

When it leaves, the Direction of the velocity will obviously will be along the tangent as its instantaneous velocity was in the direction of tangent.

Hence, Option (c). is correct answer.

Hope it helps.