Question

A stone of mass m1 moving with uniform speed v suddenly ecplodes on its own into twi if fragment of mass m2 is at rest speed if other is

Answer 1

I don't understand the question properly..but I can answer you...tell is it right or not..

so by momentum conservation...

m1 × v = m2 × 0 + m' × v'

( assuming m1 divided into two parts first is m2 which is on rest and another is m' which have velocity v')

so v' = m1 . v / m'

tell me...this is right or not..

Answer 2

Answer:

Explanation:

Initial momentum = final momentum

mv = m​​1(0) + (m-m1)v2

where m1 is the mass of the first fragment which is at rest i.e v1 = 0

m-m1 = mass of the second fragment moving with velocity v2.

v2 = mv(m−m1)