Question

A stone of weight 3kg tied to a string is being rotated in horizontal circle of radius 120 CM with a velocity of 500 m/ sec find the total force

Answer 1

Explanation:

centripetal force = m*v^2/r

= (3*500^2)/0.12

= 6250000 N

Answer 2

The total force acting on the stone is $F=6.25\times 10^5\ N$.

Explanation:

Given that,

Mass of the stone, m = 3 kg

Radius of the string, r = 120 cm = 1.2 m

Velocity of the stone, v = 500 m/s

We need to find the total force. The force acting on the object when it moves in a circle is called centripetal force. It is given by :

$F=\dfrac{mv^2}{r}$

$F=\dfrac{3\times (500)^2}{1.2}$

$F=6.25\times 10^5\ N$

So, the total force acting on the stone is $F=6.25\times 10^5\ N$. Hence, this is the required solution.

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