Question

A stone projected at a speed 20 m/s at an
angle 60' with horizontal. When the stone
is moving horizontally, then the angular
velocity about the point of projection is
1) 1 rad/s
2) 1/2 rad/s
3) 1/3 rad/s
4) 1/4 rad/s
Take 50 points but please answer​

Answer 1

Answer:

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Explanation:

answer is 1/4 rad/s

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Answer 2

The velocity of the stone(v) = $20\frac{m}{s}$

The angle made with the horizontal($\theta$)=$60\textdegree$

Angular velocity about the point of projection($\omega$)=?

Radius can be given by=$\frac{v^{2} }{gcos\theta}$

Radius can also be given =$\frac{v}{\omega}$

Equating the radius = $\frac{v^{2} }{gcos\theta}=\frac{v}{\omega}$

Angular velocity about the point of projection($\omega$)=$\omega=\frac{gcos\theta}{v}$

$\omega=\frac{10\times cos60\textdegree}{20} =\frac{1}{2\times2} =\frac{1}{4} rad/s$

Hence, the correct option is 4) 1/4 rad/s.