a stone projected up with velocity u reaches 2 points A and B at distance h with velocity u/2 and u/3 then the maximum height reached by it is
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Answer:
A stone projected upwards with a velocity 'u' reaches two points 'P' and 'Q' separated by a distance
'h' with velocities u/2 and u/3. The maximum height reached by it is 36h/5
Explanation:
Two points 'P' and 'Q' separated by a distance 'h' with velocities u/2 and u/3
v^2=u^2−2gh
⇒(u/3)^2=(u/2)^2−2gh
⇒5u^2/36 =2gh
⇒u^2/2g=36/5h
Maximum height reached by the stone
hmax=u^2/2g=36/5h
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