Physics, asked by bhuvaneshreddy876, 10 months ago

a stone projected up with velocity u reaches 2 points A and B at distance h with velocity u/2 and u/3 then the maximum height reached by it is​

Answers

Answered by MяMαgıcıαη
62

Answer:

A stone projected upwards with a velocity 'u' reaches two points 'P' and 'Q' separated by a distance

'h' with velocities u/2 and u/3. The maximum height reached by it is 36h/5

Explanation:

Two points 'P' and 'Q' separated by a distance  'h' with velocities u/2 and u/3

v^2=u^2−2gh

⇒(u/3)^2=(u/2)^2−2gh

⇒5u^2/36 =2gh

⇒u^2/2g=36/5h

Maximum height reached by the stone

hmax=u^2/2g=36/5h

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