Question

A stone projected upwards with a velocity 'u' reaches two points 'P' and 'Q' separated by a distance
'h' with velocities u/2 and u/3. The maximum height reached bt it is​

Answer 1

Answer:

A stone projected upwards with a velocity 'u' reaches two points 'P' and 'Q' separated by a distance

'h' with velocities u/2 and u/3. The maximum height reached by it is​ 36h/5

Explanation:

Two points 'P' and 'Q' separated by a distance  'h' with velocities u/2 and u/3

v^2=u^2−2gh

⇒(u/3)^2=(u/2)^2−2gh

⇒5u^2/36 =2gh

⇒u^2/2g=36/5h

Maximum height reached by the stone

hmax=u^2/2g=36/5h

Answer 2

Answer:

A stone projected upwards with a velocity 'u' reaches two points 'P' and 'Q' separated by a distance

'h' with velocities u/2 and u/3. The maximum height reached by it is​ 36h/5

Explanation:

Two points 'P' and 'Q' separated by a distance  'h' with velocities u/2 and u/3

v^2=u^2−2gh

⇒(u/3)^2=(u/2)^2−2gh

⇒5u^2/36 =2gh

⇒u^2/2g=36/5h

Maximum height reached by the stone

hmax=u^2/2g=36/5h