Question

A stone projected vertically up from the ground reaches a
height y in its path at t1, seconds and after further t2, seconds
reaches the ground. The height y is equal to?​

Answer 1

Answer:

21 gt 1t 2y=ut 1− 21gt 12

⇓t 1+t 2

= g2u(total time of journey)

So, u=g 2(t 1+t 2 )

⇒y=g 2(t 1+t 2 ) t 1 − 21 gt 12

= 21 gt 1t 2