a stone projected vertically up with velocity 5m/s from the top of the tower reaches the ground with velocity 10m/s . the height of the tower is
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11th
Physics
Motion in a Straight Line
Problems on Equation of Motion
An object projected vertica...
PHYSICS
An object projected vertically up from the top of the tower took 5 s to reach the ground. The average velocity of the object is 5ms
−1
), find its average speed. (given g =10ms
−1
).
December 26, 2019avatar
Priyadarshini Kallepalli
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ANSWER
Height of tower= displacement of an object= average velocity × time=5×5=25m,
Let initial velocity of the object is u.
Using s=ut+
2
1
at
2
, ⇒−25=u×5−
2
1
g×5
2
⇒u=20ms
−1
,
Now from the tower,Let maximum height reached by object is h.
At maximum height velocity v=0,
Using v
2
=u
2
+2as ⇒0=20
2
−2gh ⇒h=20m,
∴ Total distance =2h+25=65m
Average speed=
Total Time
Total Distance
,
⇒ Average speed=
5
65
=13ms
−1
Explanation:
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