Physics, asked by bhanu5841, 10 months ago

- A stone projected vertically up with velocity
v from the top of a tower reaches the ground
with velocity 2v. The height of the tower is

Answers

Answered by qwtiger
50

Answer:

The height of the tower is 3v^2/2g

Explanation:

Let the height of the tower is h

According to the problem the stone is projected upwards with the velocity v and touches the ground with the velocity 2v

Now we know that

v^2- u^2= 2gh

(2v)^2- v^2= 2gh

4v^2- v^2= 2gh

3 v^2= 2gh

h= 3v^2/2g

Hence the answer will be 3v^2/2g

Answered by nishwin
4

Answer:

3v^2/2g

Explanation:

It is the correct answer

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