- A stone projected vertically up with velocity
v from the top of a tower reaches the ground
with velocity 2v. The height of the tower is
Answers
Answered by
50
Answer:
The height of the tower is 3v^2/2g
Explanation:
Let the height of the tower is h
According to the problem the stone is projected upwards with the velocity v and touches the ground with the velocity 2v
Now we know that
v^2- u^2= 2gh
(2v)^2- v^2= 2gh
4v^2- v^2= 2gh
3 v^2= 2gh
h= 3v^2/2g
Hence the answer will be 3v^2/2g
Answered by
4
Answer:
3v^2/2g
Explanation:
It is the correct answer
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