Question

a stone protected up vertically with a velocity 19.6m/s reaches certain height in its path at 1second after how many more seconds it reaches ground​

Answer 1

Answer:

4 sec

Explanation:

v = 19.6 m/s

g = 9.8 m/s

so time to reach ground by stone is given by

t = 2u/g

this gives time of flight = 2 × 19.6 / 9.8 = 4 sec