Question

A stone release from top of the tower of hight 19.6 m calculate its finial velocity if the acceleration is 9.8 metre per second square​

Answer 1

Answer:

192.08 metre per second

Answer 2

Answer:

acceleration=9.8m/s^2

height =19.6 m

$v ^{2} - {u}^{2} = 2as$

${v}^{2} = 2 \times 9.8 \times 19.6$

$v = 19.6$

final velocity=19.6 m/s