Question

A stone released with zero velocity from top of the tower reaches the ground in 4s.The height of the tower is ​

Answer 1

Answer:

Using the formula s=ut+(1/2)at^2

Here u= initial velocity

t= time period

a= acceleration due to gravity

s= height of tower

Therefore, s= 0×4+(10×16)/2

s= 160/2

s= 80m

Therefore the height of the tower is 80m.