A stone's throw from a river bank.Height, h in meters, the stone in
the stone in time t sconds after was thrown is h = 40t-5r^{2} .
when does the stone reach the surface of the water?
Answers
Answered by
0
Step-by-step explanation:
just differentiate them u get 10r use h=1/2at² u get urs answer perfectly
Answered by
0
When particle is dropped from bridge the initial velocity u is zero.
Let the height of bridge from water level is h then the displacement traveled by particle is h.
Acceleration is g downward.
Then applying equation of motion:
s=ut+
2
1
at
2
where a=g and u=0
then, h=
2
1
g(1)
2
=
2
1
×9.8=4.9m
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