A stone so dropped from the top of a tower of height 125m.The distance travelled by it during last second of its fall is
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Answered by
1
hey frnd,
S= ut + 1/2(a*t^2)
S = 0.5 * 10 * 3^3
S = 45m
Distance traveled in last second = 45m
S= ut + 1/2(a*t^2)
S = 0.5 * 10 * 3^3
S = 45m
Distance traveled in last second = 45m
Answered by
0
Answer:45m
Explanation:note that first we have to find time,then find the distance using the time obtained as the last second
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